How many kWh will this pump use?

Osmigo

Well-known member
Jan 21, 2024
51
Comfort, Texas
Pool Size
8600
Surface
Plaster
Chlorine
Liquid Chlorine
Our pool will come with a Hayward Tristar XE 1.85THP. I'm trying to get an approximate picture of how much electricity it will use. It's Energy Star rated, super-efficient, etc.

Does anybody know how many amps it uses at different RPMs, or how many kWh? I can't find this information anywhere. I know our electric co. charges 8.02 cents per kWh, so if I could get this information, I could calculate its approximate monthly cost.
 
Our pool will come with a Hayward Tristar XE 1.85THP. I'm trying to get an approximate picture of how much electricity it will use. It's Energy Star rated, super-efficient, etc.

Does anybody know how many amps it uses at different RPMs, or how many kWh? I can't find this information anywhere. I know our electric co. charges 8.02 cents per kWh, so if I could get this information, I could calculate its approximate monthly cost.
At $.08002/kwh you could probably run it 24/7 at about 75% speed for $20.00/month or less.
 
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Man, you guys are awesome. Thanks. I have a brochure for the Hayward HeatPro 100K BTU heater/chiller. It says "minimum circuit amps" is 42. It runs on 220V. 220 X 42 = 9240 = 9.24 Kw.
So 9.24 Kwh X $.0802 per Kwh = $.74. So it would cost about 74 cents per hour to operate. ...?
 

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It comes with the HP31005T. kW input is 4.7. So the amps x voltage approach is incorrect? That's encouraging - comes out to about 38 cents an hour.
The manual indicates the maximum amp-draw of that model is 31.2 while running. If you are using true 220v, it will use about 6.9kW/hr. At your rate that is about $.56/hour to heat.
 
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"Some think the compressor's rated load amperage (RLA) is its running amperage. This is not so.

RLA is not the running amperage of the compressor; it is a mathematical formula and is used for such things as sizing fuses, wires, and contactors."


 
According to the graph posted earlier, the pump has a water flow of 55 to 140 GPM. The specs on the HeatPro list a min/max flow of 30 to 75 GPM, with a reccomended flow of 43 GPM. Is that going to be an issue?
 
The flow depends on the System Curve.

If we estimate the System Curve to be the red line, then the flow is where the system curve crosses the pump performance curve.

To get 40 GPM, you would use about 1,725 RPM, which uses about 206 watts.

1,920 RPM will give you about 44 GPM at about 285 watts.

2,115 RPM will give you about 48 GPM at about 380 watts.


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The amount of “Real” power is what is measured by the meter from your power company in most cases.

Real power is volts x Amps x Power Factor.

If the Real Power is 4.7 Kw, then the measured amperage at 230 volts and a power factor of 0.94 should be about:

4,700 Watts = (0.94)(A)(230).

A = 21.74 Amps.

The measured amperage should be about 70% of the RLA (Rated Load Amperage).

21.74/31.2 = 70%.

Apparent Power will be about 5,000 watts.

Apparent Power is Volts x Amps.

Reactive Power will be about 300 watts.

Reactive Power is Apparent Power - Real Power.
 
First buy cheap amp clamp from Harbor Freight < $20. Then use the above equation to find watts. Do that for several different speeds. That is the ONLY way to know what your cost is.
Besides it is kinka fun.
 

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