Another Heat pump Recommendation

gctnj

0
Bronze Supporter
Jun 28, 2016
33
Wayne, NJ
Pool Size
27000
I am redoing all my equipment. I am now at the point of picking a heat pump. We are in NJ, just want a warmer pool during the summer and extend the session a week or two. I am looking at Aquacal and Raypak. Reliability is important, but since the equipment is close to the property line and the neighbors, I would like it to be as quiet as possible? Opinions? As a side question, is it worth waiting to see if manufacturers are moving to r32 or r454b from r410a?
 
I’ve read almost everything here and on Reddit for the past few months. Lots of good heat pumps, but based on reading I selected Aqualcal and Raypak. Hard online to find out which is quieter. Which besides decent reliability, is most important to me. So if anyone has heard both, let me know. Raypak is used locally quite a bit here, not sure about Aquacal. The R-410 question wouldn’t stop me from getting one. I’m just interested if pool heat pumps are moving off of it like HVAC manufacturers
 
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@Davegnh @PoolBrews had a discussion about Aquacal noise on this thread…

 
Interesting post on the Aquacal. After calling local pool stores, not one has said they sell or repair Aquacal. I may need to move Hayward up in the list next to Raypak. My local stores sell both. I’m going to visit my local stores to discuss.
 
We like the pool at 85 degrees. It is covered. We just want to heat during the summer when needed and maybe extend the season a week or two at the start and end of the season (Late May and mid September). Lowest temperature we would heat the pool is 55-60 and only if the daytime temperature would be above 60.
 

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At 60 air temp and 85 water temp, I estimate a heat loss of about 92,250 btu/hr.

If the heat pump puts out 100,000 btu/hr, the heat pump will need to run about 92% of the time to maintain the temp.

The formula for heating is estimated to be Y=87.07−27.07e^(−0.01702x), where Y is temp and X is time in hours.

You should get about 0.46 degrees per hour gain and the loss depends on the water temp.

The estimated time to heat to 85 is 151 hours.

Max temp is 87 degrees.

Note that due to heat loss, the time required to go up by one degree increases as the temp increases.

For example, the time to go from 60 to 61 degrees is 2.21 hours.

The time to go from 84 to 85 degrees is 23 hours, which is more than 10 times as long.
1743261172309.png
____________________________________________________________________________________________________________
Temperature = (1/3690) * Heat Loss + 60
Y = Temperature.
X= Heat Loss.
Y = 0.000271X + 60

1743262334807.png
____________________________________________________________________________________________________________
Y = Temperature.
X= Time in hours.
Y=87.07−27.07e^(−0.01702x)
1743262766809.png


Pool Temperature vs. Time​

Temperature (°F)Time (hours)
60.000.00
61.002.21
62.004.51
63.006.90
64.009.39
65.0012.00
66.0014.72
67.0017.58
68.0020.58
69.0023.75
70.0027.09
71.0030.64
72.0034.41
73.0038.45
74.0042.78
75.0047.46
76.0052.54
77.0058.10
78.0064.25
79.0071.11
80.0078.88
81.0087.84
82.0098.42
83.00111.33
84.00127.89
85.00151.05
86.00189.82
87.00350.04
 
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With the solar cover on, we almost never go below 70 degrees pool temperature the last two weeks of May and the first two weeks of September. With the solar cover, we are usually mid to upper 70s. Using the pool for those weeks would be great, but the last few seasons we almost never maintain 85 degrees during June, July, August. Our hope and focus is that the heat pump keeps us at 85 for the those three months. In May and September, we wouldn’t turn on the heater unless air temperature was > 55 and wouldn’t go in the pool unless daytime temperature was > 60.
 
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Assuming no heat loss at 70 and 50,000 btu/hr heat loss at 85 degrees, we get

y = 0.0003x + 70

y = temperature.

X = heat loss in btu/hr/

1743345023940.png
______________________________________________________________________________________________________________

Using 115,000 btu/hr as the heat input and the formula for heat loss vs. temp, we can estimate the equation for temp vs. time to be:

Y = 104.5 - 34.5(e^(-0.01539077x))

y = temp.

x = time in hours.

Time to get to 85 degrees is about 37 hours.

1743345465564.png
 
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Different assumptions give different results.

The main goal is to get an approximate idea about how a heat pump will perform.

Heat loss at 85 degrees is estimated at 50,000 to 75,000 btu/hr. while covered.

Uncovered will be 2 to 3 times the heat loss.

If the heat pump puts out 115,000 btu/hr, then the heat pump will need to run 43% to 65% to maintain 85 degrees while covered.

Uncovered, the pool will probably lose more heat than the heat pump can produce and the temp will probably go down some when uncovered.

y = 0.000348x + 60.

85 degrees = 71,839 btu/hr loss.

70 degrees takes 21.63 hours.

85 degrees takes 73.75 hours.

70 to 85 = 52.12 hours.

1743348892697.png
_________________________________________________________________________________
y = 100 - 40e^(-0.0133x).

Y= Temperature.
X = Time in hours.

1743348624953.png